Image processing - lane line recognition (simple)

For example, there is no advanced identification yet. The identified lanes are still within the intercepted target range. Only one lane line on the left and right can be identified correctly
Because the straight line fitting part uses the least square fitting, the result is quasi skew

I haven't thought of a better way yet. I'll change it when I think of it

import cv2
import numpy as np

#Read image and gray image processing

#canny marginalization
edges=cv2.Canny(grap, 50, 200, 3)

#Get picture size

#Obtain the target area according to the size

#hough transform 
minLineLength = 1
maxLineGap = 0
lines = cv2.HoughLinesP(load, 1, np.pi / 180, 10, minLineLength, maxLineGap)

#Fitting lane lines using least squares
left_lines_x = []
left_lines_y = []
right_lines_x = []
right_lines_y = []
line_y_max = 0
line_y_min = 999
for line in lines:
    for x1, y1, x2, y2 in line:
        if y1 > line_y_max:
            line_y_max = y1
        if y2 > line_y_max:
            line_y_max = y2
        if y1 < line_y_min:
            line_y_min = y1
        if y2 < line_y_min:
            line_y_min = y2
        k = (y2 - y1) / (x2 - x1)
        if k < -0.3:
        elif k > 0.3:
# Least square line fitting
left_line_k, left_line_b = np.polyfit(left_lines_x, left_lines_y, 1)
right_line_k, right_line_b = np.polyfit(right_lines_x, right_lines_y, 1)

# The corresponding x is inversely calculated according to the linear equation and the maximum and minimum y values
         (int((line_y_max - left_line_b) / left_line_k), line_y_max),
         (int((line_y_min - left_line_b) / left_line_k), line_y_min),
         color, thickness)
         (int((line_y_max - right_line_b) / right_line_k), line_y_max),
         (int((line_y_min - right_line_b) / right_line_k), line_y_min),
         color, thickness)


There are a few troublesome functions in the middle
HoughlinesP() must add P at the end, and the returned value is the coordinates (x1,y1),(x2,y2) of the first and last two points of a line segment
Houghlines() returns a vector representation of two elements without P( ρ,Θ), among ρ Is the distance from the coordinate origin ((0,0) (that is, the upper left corner of the image). Θ Is the rotation angle of the arc line.

HoughLinesP(image,rho,theta,threshold,minLineLength=0,maxLineGap=0 )

Then there is the parameter problem. Houghlines() is not easy to use, but sometimes it may be OK
1. The first parameter of HoughLinesP() is the same as Houghlines(). image is a picture. Here, it must be a binary picture (I understand that ordinary images are ternary, R,G,B or H,S,V, and the binary is only 0 and 1). In order to prevent the picture type from changing somewhere, it's best to gray process it again before use


So it must be a binary image
2. rho and theta are the distance accuracy in pixels and the angle accuracy in radians, respectively, which are usually set to 1 and 2 Π 180 \frac{Π}{180} one hundred and eighty Π It's not a big problem.
3. Threshold, the threshold parameter of the accumulation plane, that is, the value that must be reached in the accumulation plane when identifying a part as a straight line in the graph. Generally speaking, it is how long the line segment can be identified as a line segment. If it is too large, some small line segments will be filtered.
4. minLineLength is also a parameter used for filtering. It can only be displayed if it is greater than this value. It looks like the function of threshold
5. maxLineGap is the maximum distance allowed to connect points in the same line to points

Then there is the image selection. At first, four exact points were used to locate the cut, but later it was found that if this was the case, the image of another size would be wrong, so the target area was located by scale

#Obtain the target area according to the size

pts is to save the coordinates of the four points. The order of the four points is connected counterclockwise from the upper right corner
cv2.fillConvexPoly() is to fill (255255255) white in the area surrounded by four points in p, AND then cv2.bitwise_and() is to AND each pixel value of p AND dst to filter out the images in the area

The following is the code to obtain the coordinates of the specified pixel points. After running, just point them directly on the graph

import cv2

def mouse(event, x, y, flags, param):
    if event == cv2.EVENT_LBUTTONDOWN:
        xy = "%d,%d" % (x, y), (x, y), 1, (255, 255, 255), thickness = -1)
        cv2.putText(img, xy, (x, y), cv2.FONT_HERSHEY_PLAIN,
                    1.0, (255, 255, 255), thickness = 1)
        cv2.imshow("image", img)

img = cv2.imread("load2.png")
cv2.imshow("image", img)
cv2.setMouseCallback("image", mouse)


Tags: image identification

Posted on Tue, 19 Oct 2021 00:09:53 -0400 by Tarsonis21