List operations in Python

Python's list manipulation is powerful and convenient (as opposed to Java)Say nothing about simple, regular operations (...
Python's list manipulation is powerful and convenient (as opposed to Java)
Say nothing about simple, regular operations (this is not an introductory tutorial) and introduce a few very specific examples

Add to
# Append to End(append) li = [1, 2, 3, 4, 5] li.append(6) print('li = %s' % li) # Output: li = [1, 2, 3, 4, 5, 6] # Append a list(extend) li2 = ['a', 'b', 'c', 'd', 'e'] li.extend(li2) print('li = %s' % li) # Output: li = [1, 2, 3, 4, 5, 6, 'a', 'b', 'c', 'd', 'e'] # Lists and lists can also be added li_plus = li + li2 print('li_plus = %s' % li_plus) # Output: li_plus = [1, 2, 3, 4, 5, 6, 'a', 'b', 'c', 'd', 'e', 'a', 'b', 'c', 'd', 'e']

delete
# Delete elements from list li = [1, 2, 3, 4, 5] li.remove(3) print('li = %s' % li) # Output: li = [1, 2, 4, 5]
# Delete elements by index del li[3] print('li = %s' % li) # Output: li = [1, 2, 4]

Interception (also known as slicing)
Format: [start:end:step].Remember this format and you can imagine it
li = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
# Take one every two elements li2 = li[::2] print('li2 = %s' % li2) # Output: li2 = [0, 2, 4, 6, 8, 10] # Last element element = li[-1] print('element = %s' % element) # Output: element = 10 # Copy (a new object after copy) li2 = list(li) print('li2 = %s' % li2) # Output: li2 = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Extract and delete (pop)
li = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] # Extract and delete the last element li.pop() # Equivalent to li.pop(-1) print('li = %s' % li) # Output: li = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] # Extract and delete the first element (or n Elements) li.pop(0) print('li = %s' % li) # Output: li = [1, 2, 3, 4, 5, 6, 7, 8, 9]

sort
# Positive Ordering li = [3, 1, 5, 8, 0, 9, 2, 6, 7, 4] li.sort() print('li = %s' % li) # Output: li = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] # Reverse order li = [3, 1, 5, 8, 0, 9, 2, 6, 7, 4] li.sort(reverse=True) print('li = %s' % li) # Output: li = [9, 8, 7, 6, 5, 4, 3, 2, 1, 0] # Flip (not in reverse order) li = [3, 1, 5, 8, 0, 9, 2, 6, 7, 4] li.reverse() print('li = %s' % li) # Output: li = [4, 7, 6, 2, 9, 0, 8, 5, 1, 3]

List Resolution
How to efficiently create a new list based on an existing list
Format: [expression for iter_val in iterable]
# Square each item in the list li = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] li2 = [i**2 for i in li] print('li2 = %s' % li2) # Output: li2 = [0, 1, 4, 9, 16, 25, 36, 49, 64, 81] # Only numbers greater than 5 are squared.The expression can also be if Sentence li = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] li2 = [i**2 if i > 5 else i for i in li] print('li2 = %s' % li2) # Output: li2 = [0, 1, 2, 3, 4, 5, 36, 49, 64, 81]
Format: [expr for iter_var in iterable if cond_expr]
# Only take non None Elements of li = [0, 1, 2, 3, 4, 5, None, 6, 7, 8, 9] li2 = [i for i in li if i is not None] print('li2 = %s' % li2) # Output: li2 = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
Format: [expr for iter_var in iterable for var in iter_var]
# Expand a two-dimensional list li = [[0, 1, 2], [3, 4, 5, 6], [7, 8, 9]] li2 = [j for i in li for j in i] print('li2 = %s' % li2) # Output: li2 = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Connect elements in the list (join)
li = ['aaa', 'bbb', 'ccc', 'ddd'] li2 = ', '.join(li) print('li2 = %s' % li2) # Output: li2 = aaa, bbb, ccc, ddd

12 July 2020, 10:52 | Views: 8597

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