The sixth Blue Bridge Cup group a C / C + + national competition in 2015

Title: magic square of fourth order Fill the numbers from 1 to 16 into the 4x4 square, so that the sum of rows, columns and two diagonals are equal, ...
Title: magic square of fourth order
Code

Title: magic square of fourth order

Fill the numbers from 1 to 16 into the 4x4 square, so that the sum of rows, columns and two diagonals are equal, which is called the fourth-order magic square when it meets such characteristics.

There may be many schemes for the fourth order magic square. If the fixed upper left corner is 1, please calculate the total number of options.
For example:
1 2 15 16
12 14 3 5
13 7 10 4
8 11 6 9

And:
1 12 13 8
2 14 7 11
15 3 10 6
16 5 4 9

It can be regarded as two different schemes.

Please submit all scheme numbers when the upper left corner is fixed to 1, and do not fill in any redundant content or explanatory text.

Code

/* ^....0 ^ .1 ^1^ .. 01 1.^ 1.0 ^ 1 ^ ^0.1 1 ^ ^..^ 0. ^ 0^ .0 1 .^ .1 ^0 .........001^ .1 1. .111100....01^ 00 11^ ^1. .1^ 1.^ ^0 0^ .^ ^0..1 .1 1..^ 1 .0 ^ ^ 00. ^^0.^ ^ 0 ^^110.^ 0 0 ^ ^^^10.01 ^^ 10 1 1 ^^^1110.1 01 10 1.1 ^^^1111110 010 01 ^^ ^^^1111^1.^ ^^^ 10 10^ 0^ 1 ^^111^^^0.1^ 1....^ 11 0 ^^11^^^ 0.. ....1^ ^ ^ 1. 0^ ^11^^^ ^ 1 111^ ^ 0. 10 00 11 ^^^^^ 1 0 1. 0^ ^0 ^0 ^^^^ 0 0. 0^ 1.0 .^ ^^^^ 1 1 .0 ^.^ ^^ 0^ ^1 ^^^^ 0. ^.1 1 ^ 11 1. ^^^ ^ ^ ..^ ^..^ ^1 ^.^ ^^^ .0 ^.0 0..^ ^0 01 ^^^ .. 0..^ 1 .. .1 ^.^ ^^^ 1 ^ ^0001 ^ 1. 00 0. ^^^ ^.0 ^.1 . 0^. ^.^ ^.^ ^^^ ..0.0 1 .^^. .^ 1001 ^^ ^^^ . 1^ . ^ ^. 11 0. 1 ^ ^^ 0. 0 ^. 0 ^0 1 ^^^ 0. 0.^ 1. 0^ 0 .1 ^^^ .. .1 1. 00 . .1 ^^^ .. 1 1. ^. 0 .^ ^^ .. 0. 1. .^ . 0 . .1 1. 01 . . ^ 0 ^.^ 00 ^0 1. ^ 1 1 .0 00 . ^^^^^^ . .^ 00 01 .. 1. 00 10 1 ^ ^.1 00 ^. ^^^ .1 .. 00 .1 1..01 .. 1.1 00 1. ..^ 10 ^ 1^ 00 ^.1 0 1 1 .1 00 00 ^ 1 ^ . 00 ^.^ 10^ ^^ 1.1 00 00 10^ ..^ 1. ^. 1. 0 1 ^. 00 00 .^ ^ ^. ^ 1 00 ^0000^ ^ 01 1 0 ^. 00.0^ ^00000 1.00.1 11 . 1 0 1^^0.01 ^^^ 01 .^ ^ 1 1^^ ^.^ 1 1 0. .. 1 ^ 1 1 ^ ^ .0 1 ^ 1 .. 1.1 ^0.0 ^ 0 1..01^^100000..0^ 1 1 ^ 1 ^^1111^ ^^ 0 ^ ^ 1 1000^ .1 ^.^ . 00 .. 1.1 0. 0 1. . 1. .^ 1. 1 1. ^0 ^ . ^.1 00 01 ^.0 001. .^ */ /* Procedural objectives: Variables required by the program: Procedural thinking: Functions required by the program: Determination algorithm: Determining data structure: */ /* My dear Max said: "I like you, So the first bunch of sunshine I saw in the morning is you, The first gentle breeze that passed through my ear is you, The first star I see is also you. The world I see is all your shadow." FIGHTING FOR OUR FUTURE!!! */ #include <iostream> #include <algorithm> using namespace std; int num[17]; int sum[11]; int ans[17]; bool vis[17]; long long temp=0; void dfs(int index){ if(index==5){ sum[1]=ans[1]+ans[2]+ans[3]+ans[4]; } if(index==9){ sum[2]=ans[5]+ans[6]+ans[7]+ans[8]; if(sum[2]!=sum[1]) return; } if(index==13){ sum[3]=ans[9]+ans[10]+ans[11]+ans[12]; if(sum[3]!=sum[1]) return; } if(index==14){ sum[5]=ans[1]+ans[5]+ans[9]+ans[13]; sum[10]=ans[4]+ans[7]+ans[10]+ans[13]; if(sum[5]!=sum[1] || sum[10]!=sum[1]) return; } if(index==15){ sum[6]=ans[2]+ans[6]+ans[10]+ans[14]; if(sum[6]!=sum[1]) return; } if(index==16){ sum[7]=ans[3]+ans[7]+ans[11]+ans[15]; if(sum[7]!=sum[1]) return; } if(index==17){ sum[4]=ans[13]+ans[14]+ans[15]+ans[16]; sum[8]=ans[4]+ans[8]+ans[12]+ans[16]; sum[9]=ans[1]+ans[6]+ans[11]+ans[16]; if(sum[4]!=sum[1] || sum[8]!=sum[1] || sum[9]!=sum[1]) return; for(int i=1;i<17;i++){ cout<<ans[i]<<' '; if(i%4==0) cout<<endl; } for(int i=1;i<11;i++){ cout<<"sum["<<i<<"]="<<sum[i]<<' '; } cout<<endl<<endl; temp++; return; } for(int i=1;i<17;i++){ if(!vis[i]){ vis[i]=true; ans[index]=i; dfs(index+1); vis[i]=false; } } } int main(){ for(int i=1;i<17;i++){ num[i]=i; vis[i]=false; } ans[1]=1;vis[1]=true; dfs(2); cout<<temp<<endl; return 0; }

6 November 2019, 11:06 | Views: 7517

Add new comment

For adding a comment, please log in
or create account

0 comments